# Pollard's p - 1 algorithm

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Pollard's p - 1 algorithm

Pollard's "p" − 1 algorithm is a number theoretic integer factorization algorithm, invented by John Pollard in 1974. It is a special-purpose algorithm, meaning that it is only suitable for integers with specific types of factors; it is the simplest example of an algebraic-group factorisation algorithm.

The factors it finds are ones for which "p"-1 is smooth; the essential observation is that, by working in the multiplicative group modulo a composite number "N", we are also working in the multiplicative groups modulo all of "N"'s factors.

The existence of this algorithm leads to the concept of safe primes, being primes for which "p-1" has at least one large prime factor. Almost all sufficiently large primes are safe; if a prime used for cryptographic purposes turns out to be unsafe, it is much more likely to be through malice than through an accident of random number generation.

Base concepts

Let "n" be a composite integer with prime factor "p". By Fermat's little theorem, we know that

:$a^\left\{K\left(p-1\right)\right\} equiv 1pmod\left\{p\right\}$ for all $K$, and for all $a$ coprime to $p$

If a number "x" is congruent to 1 modulo a factor of "n", then the gcd ("x-1","n") will be divisible by that factor.

The idea is to make the exponent a large multiple of "p"-1 by making it a number with very many prime factors; generally, we take the product of all prime powers less than some limit "B". Start with a random "x", and repeatedly replace it by $x^w mod n$ as "w" runs through those prime powers. Check at each stage, or once at the end if you prefer, whether ("x-1","n") is not equal to 1.

Multiple factors

It is possible that for all the prime factors p of "n", p-1 is divisible by small primes, at which point the Pollard p-1 algorithm gives you "n" again.

Algorithm and running time

The basic algorithm can be written as follows:

:Inputs: "n": a composite integer:Output: a non-trivial factor of "n" or failure

:# select a smoothness bound "B":# randomly pick "a" coprime to "n" (note: we can actually fix "a", random selection here is not imperative):# for each prime "q" ≤ "B":#::#:$a gets a^\left\{q^e\right\} mod\left\{n\right\}$ (note: this is "a""M"):# "g" ← gcd("a" − 1, "n"):# if 1 < "g" < "n" then return "g":# if "g" = 1 then select a higher "B" and go to step 2 or return failure:# if "g" = "n" then go to step 2 or return failure

If "g" = 1 in step 6, this indicates that for all "p" − 1 that none were "B"-powersmooth. If "g" = "n" in step 7, this usually indicates that all factors were "B"-powersmooth, but in rare cases it could indicate that "a" had a small order modulo "n".

The running time of this algorithm is O("B" &times; log "B" &times; log2"n"); larger values of "B" make it run more slowly, but are more likely to produce a factor

How do you pick "B"?

Since the algorithm is incremental, you can just leave it running with the bound constantly increasing.

Assume that $p-1$, where $p$ is the smallest prime factor of "n", can be modelled as a random number of size less than $sqrt n$. By Dickson's theorem, the probability that the largest factor of such a number is less than $\left(p-1\right)^epsilon$ is roughly $epsilon^\left\{-epsilon\right\}$; so there is a probability of about $3^\left\{-3\right\} = 1/27$ that a "B" value of $n^\left\{1/6\right\}$ will yield a factorisation.

In practice, the elliptic curve method is faster than the Pollard p-1 method once the factors are at all large; you might run the p-1 method up to $B=10^6$, which will find a quarter of all twelve-digit factors and 1/27 of all eighteen-digit factors, before proceeding to another method.

Large prime variant

A variant of the basic algorithm is sometimes used; instead of requiring that $p-1$ has all its factors less than B, we can require it to have all but one of its factors less than some B1, and the remaining factor less than some B2. Let $p_1$ be the smallest prime greater than B1, $p_2$ the next-largest, and so on; let $d_n = p_n - p_\left\{n-1\right\}$. The distribution of prime numbers is such that the $d_n$ will all be fairly small.

Having computed $c = a^M mod n$, we can easily compute once and for all $E_r = c^r mod n$ for all $r$ which appear as a value of $d_n$. Compute $t_1 = c^\left\{p_1\right\} mod n$. We can then stop doing exponentiation, and compute

$t_2 \left(= c^\left\{p_2\right\} mod n\right) = t_1 E_\left\{d_2\right\} mod n$, $t_3 = t_2 E_\left\{d_3\right\} mod n$, ...

with one multiplication rather than one exponentiation at each step; this is quicker by roughly a factor \$log B\$ than doing the exponentiations. It can also be accelerated significantly using Fast Fourier transforms.

Implementations

The [http://gforge.inria.fr/projects/ecm/ GMP-ECM] package includes an efficient implementation of the p-1 method.

References

*J.M. Pollard. "Theorems of Factorization and Primality Testing", "Proceedings of the Cambridge Philosophical Society" 76 (1974), pp. 521–528.

*De icon [http://zeta24.com/prim/pminus1big.php Factoring applet that uses p-1]
* [http://ardoino.com/maths-factoring-pollard/ Pollard p-1 C source code]

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