- Finite difference method
In

mathematics ,**finite-difference methods**arenumerical methods for approximating the solutions todifferential equations usingfinite difference equations to approximate derivatives.**Intuitive derivation**Finite-difference methods approximate the solutions to differential equations by replacing derivative expressions with approximately equivalent

difference quotient s. That is, because the first derivative of a function f is, by definition,:$f\text{'}(a)=lim\_\{h\; o\; 0\}\{f(a+h)-f(a)over\; h\},$then a reasonable approximation for that derivative would be to take:$f\text{'}(a)approx\; \{f(a+h)-f(a)over\; h\}$for some small value of h. In fact, this is the forward difference equation for the first derivative. Using this and similar formulae to replace derivative expressions in differential equations, one can approximate their solutions without the need for calculus.**Derivation from Taylor's polynomial**Assuming the function whose derivatives are to be approximated is properly-behaved, by

Taylor's theorem ,:$f(x\_0\; +\; h)\; =\; f(x\_0)\; +\; frac\{f\text{'}(x\_0)\}\{1!\}h\; +\; frac\{f^\{(2)\}(x\_0)\}\{2!\}h^2\; +\; cdots\; +\; frac\{f^\{(n)\}(x\_0)\}\{n!\}h^n\; +\; R\_n(x),$

where "n"! denotes the

factorial of "n", and "R"_{"n"}("x") is a remainder term, denoting the difference between the Taylor polynomial of degree "n" and the original function. Again using the first derivative of the function "f" as an example, by Taylor's theorem,:$f(x\_0\; +\; h)\; =\; f(x\_0)\; +\; f\text{'}(x\_0)h\; +\; R\_1(x),$

which, with some minor algebraic manipulation, is equivalent to

:$f\text{'}(a)\; =\; \{f(a+h)-f(a)over\; h\}\; +\; R\_1(x)$

so that for $R\_1(x)$ sufficiently small,

:$f\text{'}(a)approx\; \{f(a+h)-f(a)over\; h\}.$

**Accuracy and order**The error in a method's solution is defined as the difference between its approximation and the exact analytical solution. The two sources of error in finite difference methods are

round-off error , the loss of precision due to computer rounding of decimal quantities, andtruncation error ordiscretization error , the difference between the exact solution of the finite difference equation and the exact quantity assuming perfect arithmetic (that is, assuming no round-off).To use a finite difference method to attempt to solve (or, more generally, approximate the solution to) a problem, one must first discretize the problem's domain. This is usually done by dividing the domain into a uniform grid (see image to the right). Note that this means that finite-difference methods produce sets of discrete numerical approximations to the derivative, often in a "time-stepping" manner.

An expression of general interest is the

local truncation error of a method. Typically expressed usingBig-O notation , local truncation error refers to the error from a single application of a method. That is, it is the quantity $f\text{'}(x\_i)\; -\; f\text{'}\_i$ if $f\text{'}(x\_i)$ refers to the exact value and $f\text{'}\_i$ to the numerical approximation. The remainder term of a Taylor polynomial is convenient for analyzing the local truncation error. Using the LaGrange form of the remainder from the Taylor polynomial for $f(x\_0\; +\; h)$, which is:$R\_n(x\_0\; +\; h)\; =\; frac\{f^\{(n+1)\}(xi)\}\{(n+1)!\}\; (h)^\{n+1\}$, where $x\_0\; <\; xi\; <\; x\_0\; +\; h$,

the dominant term of the local truncation error can be discovered. For example, again using the forward-difference formula for the first derivative, knowing that $f(x\_i)=f(x\_0+i\; h)$,

:$f(x\_0\; +\; i\; h)\; =\; f(x\_0)\; +\; f\text{\'}(x\_0)i\; h\; +\; frac\{f"(xi)\}\{2!\}\; (i\; h)^\{2\},$

and with some algebraic manipulation, this leads to

:$frac\{f(x\_0\; +\; i\; h)\; -\; f(x\_0)\}\{i\; h\}\; =\; f\text{\'}(x\_0)\; +\; frac\{f"(xi)\}\{2!\}\; i\; h,$

and further noting that the quantity on the left is the approximation from the finite difference method and that the quantity on the right is the exact quantity of interest plus a remainder, clearly that remainder is the local truncation error. A final expression of this example and its order is:

:$frac\{f(x\_0\; +\; i\; h)\; -\; f(x\_0)\}\{i\; h\}\; =\; f\text{'}(x\_0)\; +\; O(h).$

This means that, in this case, the local truncation error is proportional to the step size.

**Example: ordinary differential equation**For example, consider the ordinary differential equation:$u\text{'}(x)\; =\; 3u(x)\; +\; 2.\; ,$The Euler method for solving this equation uses the finite difference quotient:$frac\{u(x+h)\; -\; u(x)\}\{h\}\; approx\; u\text{'}(x)$to approximate the differential equation by:$u(x+h)\; =\; u(x)\; +\; h(3u(x)+2).\; ,$The last equation is a finite-difference equation, and solving this equation gives an approximate solution to the differential equation.

**Example: The heat equation**Consider the normalized

heat equation in one dimension, with homogeneousDirichlet boundary condition s:$U\_t=U\_\{xx\}\; ,$:$U(0,t)=U(1,t)=0\; ,$ (boundary condition):$U(x,0)\; =U\_0(x)\; ,$ (initial condition)

One way to numerically solve this equation is to approximate all the derivatives by finite differences. We partition the domain in space using a mesh $x\_0,\; ...,\; x\_J$ and in time using a mesh $t\_0,\; ....,\; t\_N$. We assume a uniform partition both in space and in time, so the difference between two consecutive space points will be "h" and between two consecutive time points will be "k". The points

:$u(x\_j,t\_n)\; =\; u\_j^n$

will represent the numerical approximation of $U(x\_j,\; t\_n).$

**Explicit method**Using a

forward difference at time $t\_n$ and a second-ordercentral difference for the space derivative at position $x\_j$ ("FTCS") we get the recurrence equation::$frac\{u\_j^\{n+1\}\; -\; u\_j^\{n\{k\}\; =frac\{u\_\{j+1\}^n\; -\; 2u\_j^n\; +\; u\_\{j-1\}^n\}\{h^2\}.\; ,$

This is an

explicit method for solving the one-dimensionalheat equation .We can obtain $u\_j^\{n+1\}$ from the other values this way:

:$u\_\{j\}^\{n+1\}\; =\; (1-2r)u\_\{j\}^\{n\}\; +\; ru\_\{j-1\}^\{n\}\; +\; ru\_\{j+1\}^\{n\}$

where $r=k/h^2.$

So, knowing the values at time "n" you can obtain the corresponding ones at time "n"+1 using this recurrence relation. $u\_0^n$ and $u\_J^n$ must be replaced by the boundary conditions, in this example they are both 0.

This explicit method is known to be

numerically stable andconvergent whenever $rle\; 1/2$. The numerical errors are proportional to the time step and the square of the space step::$Delta\; u\; =\; O(k)+O(h^2)\; ,$**Implicit method**If we use the

backward difference at time $t\_\{n+1\}$ and a second-order central difference for the space derivative at position $x\_j$ ("BTCS") we get the recurrence equation::$frac\{u\_\{j\}^\{n+1\}\; -\; u\_\{j\}^\{n\{k\}\; =frac\{u\_\{j+1\}^\{n+1\}\; -\; 2u\_\{j\}^\{n+1\}\; +\; u\_\{j-1\}^\{n+1\{h^2\}.\; ,$

This is an

implicit method for solving the one-dimensionalheat equation .We can obtain $u\_j^\{n+1\}$ from solving a system of linear equations:

:$(1+2r)u\_j^\{n+1\}\; -\; ru\_\{j-1\}^\{n+1\}\; -\; ru\_\{j+1\}^\{n+1\}=\; u\_\{j\}^\{n\}$

The scheme is always

numerically stable andconvergent but usually more numerically intensive than the explicit method as it requires solving a system of numerical equations on each time step. The errors are linear over the time step and quadratic over the space step.**Crank-Nicolson method**Finally if we use the central difference at time $t\_\{n+1/2\}$ and a second-order central difference for the space derivative at position $x\_j$ ("CTCS") we get the recurrence equation:

:$frac\{u\_j^\{n+1\}\; -\; u\_j^\{n\{k\}\; =\; frac\{1\}\{2\}\; left(frac\{u\_\{j+1\}^\{n+1\}\; -\; 2u\_j^\{n+1\}\; +\; u\_\{j-1\}^\{n+1\{h^2\}+frac\{u\_\{j+1\}^\{n\}\; -\; 2u\_j^\{n\}\; +\; u\_\{j-1\}^\{n\{h^2\}\; ight).,$

This formula is known as the

Crank-Nicolson method .We can obtain $u\_j^\{n+1\}$ from solving a system of linear equations:

:$(2+2r)u\_j^\{n+1\}\; -\; ru\_\{j-1\}^\{n+1\}\; -\; ru\_\{j+1\}^\{n+1\}=\; (2-2r)u\_j^n\; +\; ru\_\{j-1\}^n\; +\; ru\_\{j+1\}^n$

The scheme is always

numerically stable andconvergent but usually more numerically intensive as it requires solving a system of numerical equations on each time step. The errors are quadratic over the time step and formally are of the fourth degree regarding the space step::$Delta\; u\; =\; O(k^2)+O(h^4).\; ,$However, near the boundaries, the error is often O("h"^{2}) instead of O("h"^{4}).Usually the Crank-Nicolson scheme is the most accurate scheme for small time steps. The explicit scheme is the least accurate and can be unstable, but is also the easiest to implement and the least numerically intensive. The implicit scheme works the best for large time steps.

**ee also***

Difference operator

*Stencil (numerical analysis)

*Five-point stencil

*Spectral method

*Lax-Richtmyer theorem **References*** K.W. Morton and D.F. Mayers, "Numerical Solution of Partial Differential Equations, An Introduction". Cambridge University Press, 2005.

* Oliver Rübenkönig, " [*http://www.imtek.de/simulation/mathematica/IMSweb/imsTOC/Lectures%20and%20Tips/Simulation%20I/FDM_introDocu.html The Finite Difference Method (FDM) - An introduction*] ", (2006)Albert Ludwigs University of Freiburg **External links*** [

*http://math.fullerton.edu/mathews/n2003/finitediffpde/FiniteDifferencePDEBib/Links/FiniteDifferencePDEBib_lnk_1.html Internet Resources for the Finite Difference Method for PDEs*]

* [*http://numericalmethods.eng.usf.edu/topics/finite_difference_method.html Finite Difference Method of Solving ODEs (Boundary Value Problems) Notes, PPT, Maple, Mathcad, Matlab, Mathematica*]

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