Physics of firearms

From the viewpoint of physics (dynamics, to be exact), a firearm, as for most weapons, is a system for delivering maximum destructive energy to the target with minimum delivery of energy on the shooter. The force and momentum delivered to the target however cannot be any more than that (due to recoil) on the shooter. This is because the force and momentum on the bullet is equal to that on the gun-shooter system.

Force

Assuming the gun and shooter are at rest, the force on the bullet is equal to that on the gun-shooter. This is due to Newton's third law of motion (For every action, there is an equal and opposite reaction). Consider a system where the gun and shooter have a combined mass M and the bullet has a mass m. When the gun is fired, the two systems move away from one another with new velocities V and v respectively. But the law of conservation of momentum states that their momenta must be equal: :$MV=mv\; qquad\; (1)$

Since force equals the rate of change in momentum and the initial momenta are zero, the force on the bullet must therefore be the same as the force on the gun/shooter.

Hollywood depictions of firearm victims being thrown through plate-glass windows are inaccurate. Were this to be the case, the shooter would also be thrown backwards with equal force. Gunshot victims frequently fall or collapse when shot; this is less a result of the momentum of the bullet pushing them over, but is primarily caused by physical damage or psychological effects, perhaps combined with being off-balance. This is not the case if the victim is hit by heavier projectiles such as 20 mm cannon shell, where the momentum effects can be enormous; this is why very few such weapons can be fired without being mounted on a weapons platform or involve a recoilless system (e.g. a recoilless rifle).

Velocity

From Eq. 1 we can write for the velocity of the gun/shooter: V = mv/M. This shows that despite the high velocity of the bullet, the small bullet-mass to shooter-mass ratio results in a low recoil velocity (V) although the force and momentum are equal.

Kinetic Energy

However, the smaller mass of the bullet, compared that of the gun-shooter system, allows significantly more kinetic energy to be imparted to the bullet than to the shooter. The kinetic energy for the two systems are for the gun-shooter system and for the bullet. The energy imparted to the shooter can then be written as::$frac\{1\}\{2\}MV^2=frac\{1\}\{2\}Mleft(frac\{mv\}\{M\}\; ight)^2=frac\{m\}\{M\}frac\{1\}\{2\}mv^2$

If we now write for the ratio of these energies we have::$frac\{frac\{1\}\{2\}MV^2\}\{frac\{1\}\{2\}mv^2\}\; =\; frac\{m\}\{M\}\; qquad\; (2)$

The ratio of the kinetic energies is the same as the ratio of the masses (and is independent of velocity). Since the mass of the bullet is much less than that of the shooter there is more kinetic energy transferred to the bullet than to the shooter. Once discharged from the weapon, the bullet's energy decays throughout its flight, until the remainder is dissipated by colliding with a target (e.g. deforming the bullet and target).

Transfer of Energy

When the bullet strikes, its high velocity and small frontal cross-section means that it will exert large stresses in any object it hits. This usually results in it penetrating any soft object, such as flesh. The energy is then dissipated in the wound track formed by the passage of the bullet. See terminal ballistics for a fuller discussion of these effects.

Bulletproof vests work by dissipating the bullet's energy in another way; the vest's material, usually Aramid (Kevlar or Twaron), works by presenting a series of material layers which catch the bullet and spread its imparted force over a larger area, hopefully bringing the round to a stop before it can penetrate into the body. While the vest can prevent a bullet from penetrating, the wearer will still be affected by the kinetic energy of the bullet, which can produce serious internal injuries.

Bullets in water

The television show "MythBusters" undertook to study the behavior of projectiles fired into water; comparing several firearms including a muzzle-loader, a Beretta 9mm semi-automatic pistol, a .357 magnum, an M1 Garand, a .50 caliber rifle, and a shotgun with a deer slug, that the lower velocity projectiles had lethal penetration at a distance of 8-10 feet, while high velocity projectiles fragmented upon contact with the water. [ [http://kwc.org/mythbusters/2005/07/mythbusters_bulletproof_water.html Episode 34: Bulletproof Water, 360 Swing] at Annotated Mythbusters] [ [http://www.buzzhumor.com/videos/11603/Mythbusters_Bullet_Proof_Water_Test video clip from Mythbusters Episode 34] ]

They followed this with an experiment on firing guns underwater, using a Beretta 9mm semi-automatic pistol, a .357 magnum, an M1 Garand, and a shotgun. While all the guns successfully fired underwater, the shotgun was completely destroyed, with the barrel splitting. The bullets were unable to provide lethal penetration after traveling two feet (approximately 0.6 meters).

The reason why is the same reaon as when someone jumps in the water, if they jump off of a tall surface and thus gaining more velocity they will hit the water harder and could possibly break bones, but if that same person jumped from a much smaller height then the risk of breaking a bone (breaking apart) is dramatically decreased.

ee also

*Ballistics

References