LU decomposition

LU decomposition

In linear algebra, LU decomposition (also called LU factorization) is a matrix decomposition which writes a matrix as the product of a lower triangular matrix and an upper triangular matrix. The product sometimes includes a permutation matrix as well. This decomposition is used in numerical analysis to solve systems of linear equations or calculate the determinant of a matrix. LU decomposition can be viewed as a matrix form of Gaussian elimination. LU decomposition was introduced by mathematician Alan Mathison Turing [1]

Contents

Definitions

Let A be a square matrix. An LU decomposition is a decomposition of the form

 A = LU, \,

where L and U are lower and upper triangular matrices (of the same size), respectively. This means that L has only zeros above the diagonal and U has only zeros below the diagonal. For a 3 \times 3 matrix, this becomes:


        \begin{bmatrix}
           a_{11} & a_{12} & a_{13} \\
           a_{21} & a_{22} & a_{23} \\
           a_{31} & a_{32} & a_{33} \\
        \end{bmatrix} =
      \begin{bmatrix}
           l_{11} & 0 & 0 \\
           l_{21} & l_{22} & 0 \\
           l_{31} & l_{32} & l_{33} \\
        \end{bmatrix}
        \begin{bmatrix}
           u_{11} & u_{12} & u_{13} \\
           0 & u_{22} & u_{23} \\
           0 & 0 & u_{33} \\
        \end{bmatrix}.
LDU decomposition of a Walsh matrix

An LDU decomposition is a decomposition of the form

 A = LDU, \,

where D is a diagonal matrix and L and U are unit triangular matrices, meaning that all the entries on the diagonals of L and U are one.

An LUP decomposition (also called a LU decomposition with partial pivoting) is a decomposition of the form

 PA = LU, \,

where L and U are again lower and upper triangular matrices and P is a permutation matrix, i.e., a matrix of zeros and ones that has exactly one entry 1 in each row and column.

An LU decomposition with full pivoting (Trefethen and Bau) takes the form

 PAQ = LU, \,

Above we required that A be a square matrix, but these decompositions can all be generalized to rectangular matrices as well. In that case, L and P are square matrices which each have the same number of rows as A, while U is exactly the same shape as A. Upper triangular should be interpreted as having only zero entries below the main diagonal, which starts at the upper left corner.

Existence and uniqueness

An invertible matrix admits an LU factorization if and only if all its leading principal minors are non-zero. The factorization is unique if we require that the diagonal of L (or U) consist of ones. The matrix has a unique LDU factorization under the same conditions.

If the matrix is singular, then an LU factorization may still exist. In fact, a square matrix of rank k has an LU factorization if the first k leading principal minors are non-zero, although the converse is not true.

The exact necessary and sufficient conditions under which a not necessarily invertible matrix over any field has an LU factorization are known. The conditions are expressed in terms of the ranks of certain submatrices. The Gaussian elimination algorithm for obtaining LU decomposition has also been extended to this most general case (Okunev & Johnson 1997).

Every invertible matrix A admits an LUP factorization.

Positive definite matrices

If the matrix A is Hermitian and positive definite, then we can arrange matters so that U is the conjugate transpose of L. In this case, we have written A as

 A = L L^{*}. \,

This decomposition is called the Cholesky decomposition. The Cholesky decomposition always exists and is unique. Furthermore, computing the Cholesky decomposition is more efficient and numerically more stable than computing some other LU decompositions.

Explicit formulation

When an LDU factorization exists and is unique there is a closed (explicit) formula for the elements of L, D, and U in terms of ratios of determinants of certain submatrices of the original matrix A (Householder 1975). In particular, D1 = A1,1 and for i = 2, \ldots, n, Di is the ratio of the ith principal submatrix to the (i − 1)th principal submatrix.

Algorithms

The LU decomposition is basically a modified form of Gaussian elimination. We transform the matrix A into an upper triangular matrix U by eliminating the entries below the main diagonal. The Doolittle algorithm does the elimination column by column starting from the left, by multiplying A to the left with atomic lower triangular matrices. It results in a unit lower triangular matrix and an upper triangular matrix. The Crout algorithm is slightly different and constructs a lower triangular matrix and a unit upper triangular matrix.

Computing the LU decomposition using either of these algorithms requires 2n3 / 3 floating point operations, ignoring lower order terms. Partial pivoting adds only a quadratic term; this is not the case for full pivoting.[2]

Doolittle algorithm

Given an N × N matrix

A = (an,n)

we define

A(0): = A

and then we iterate n = 1,...,N-1 as follows.

We eliminate the matrix elements below the main diagonal in the n-th column of A(n-1) by adding to the i-th row of this matrix the n-th row multiplied by

l_{i,n} := -\frac{a_{i,n}^{(n-1)}}{a_{n,n}^{(n-1)}}

for i = n+1,\ldots,N. This can be done by multiplying A(n-1) to the left with the lower triangular matrix


L_n =
\begin{pmatrix}
     1 &        &           &         &         & 0 \\
       & \ddots &           &         &         &   \\
       &        &         1 &         &         &   \\
       &        & l_{n+1,n} &  \ddots &         &   \\
       &        &    \vdots &         &  \ddots &   \\
     0 &        &   l_{N,n} &         &         & 1 \\
\end{pmatrix}.

We set

A(n): = LnA(n − 1).

After N-1 steps, we eliminated all the matrix elements below the main diagonal, so we obtain an upper triangular matrix A(N-1). We find the decomposition


A = L_{1}^{-1} L_{1} A^{(0)}
= L_{1}^{-1} A^{(1)} = L_{1}^{-1} L_{2}^{-1} L_{2} A^{(1)} = 
L_{1}^{-1}L_{2}^{-1} A^{(2)} =\ldots = L_{1}^{-1} \ldots L_{N-1}^{-1} A^{(N-1)}.

Denote the upper triangular matrix A(N-1) by U, and L=L_{1}^{-1} \ldots L_{N-1}^{-1}. Because the inverse of a lower triangular matrix Ln is again a lower triangular matrix, and the multiplication of two lower triangular matrices is again a lower triangular matrix, it follows that L is a lower triangular matrix. Moreover, it can be seen that


L =
\begin{pmatrix}
       1 &        &            &        &            & 0 \\
-l_{2,1} & \ddots &            &        &            &   \\
         &        &          1 &        &            &   \\
  \vdots &        & -l_{n+1,n} & \ddots &            &   \\
         &        &     \vdots &        &       1    &   \\
-l_{N,1} &        & -l_{N,n}   &        & -l_{N,N-1} & 1 \\
\end{pmatrix}.

We obtain A = LU.

It is clear that in order for this algorithm to work, one needs to have a_{n,n}^{(n-1)}\not=0 at each step (see the definition of li,n). If this assumption fails at some point, one needs to interchange n-th row with another row below it before continuing. This is why the LU decomposition in general looks like P − 1A = LU.

Crout and LUP algorithms

The LUP decomposition algorithm by Cormen et al. generalizes Crout matrix decomposition. It can be described as follows.

  1. If A has a nonzero entry in its first row, then take a permutation matrix P1 such that AP1 has a nonzero entry in its upper left corner. Otherwise, take for P1 the identity matrix. Let A1 = AP1.
  2. Let A2 be the matrix that one gets from A1 by deleting both the first row and the first column. Decompose A2 = L2U2P2 recursively. Make L from L2 by first adding a zero row above and then adding the first column of A1 at the left.
  3. Make U3 from U2 by first adding a zero row above and a zero column at the left and then replacing the upper left entry (which is 0 at this point) by 1. Make P3 from P2 in a similar manner and define A3 = A1 / P3 = AP1 / P3. Let P be the inverse of P1 / P3.
  4. At this point, A3 is the same as LU3, except (possibly) at the first row. If the first row of A is zero, then A3 = LU3, since both have first row zero, and A = LU3P follows, as desired. Otherwise, A3 and LU3 have the same nonzero entry in the upper left corner, and A3 = LU3U1 for some upper triangular square matrix U1 with ones on the diagonal (U1 clears entries of LU3 and adds entries of A3 by way of the upper left corner). Now A = LU3U1P is a decomposition of the desired form.

Theoretical complexity

If two matrices of order n can be multiplied in time M(n), where M(n)≥na for some a>2, then the LU decomposition can be computed in time O(M(n)).[3] This means, for example, that an O(n2.376) algorithm exists based on the Coppersmith–Winograd algorithm.

Small example


        \begin{bmatrix}
           4 & 3 \\
           6 & 3 \\
        \end{bmatrix} =
      \begin{bmatrix}
           l_{11} & 0 \\
           l_{21} & l_{22} \\
        \end{bmatrix}
        \begin{bmatrix}
           u_{11} & u_{12} \\
           0 & u_{22} \\
        \end{bmatrix}.

One way of finding the LU decomposition of this simple matrix would be to simply solve the linear equations by inspection. You know that:

l_{11} \cdot u_{11} + 0 \cdot 0 = 4
l_{11} \cdot u_{12} + 0 \cdot u_{22} = 3
l_{21}\cdot u_{11} + l_{22} \cdot 0 = 6
l_{21}\cdot u_{12} + l_{22} \cdot u_{22} = 3.

Such a system of equations is underdetermined. In this case any two non-zero elements of L and U matrices are parameters of the solution and can be set arbitrarily to any non-zero value. Therefore to find the unique LU decomposition, it is necessary to put some restriction on L and U matrices. For example, we can require the lower triangular matrix L to be a unit one (i.e. set all the entries of its main diagonal to ones). Then the system of equations has the following solution:

l21 = 1.5
u11 = 4
u12 = 3
u22 = − 1.5.

Substituting these values into the LU decomposition above:


        \begin{bmatrix}
           4 & 3 \\
           6 & 3 \\
        \end{bmatrix} =
      \begin{bmatrix}
           1 & 0 \\
           1.5 & 1 \\
        \end{bmatrix}
        \begin{bmatrix}
           4 & 3 \\
           0 & -1.5 \\
        \end{bmatrix}.

Sparse matrix decomposition

Special algorithms have been developed for factorizing large sparse matrices. These algorithms attempt to find sparse factors L and U. Ideally, the cost of computation is determined by the number of nonzero entries, rather than by the size of the matrix.

These algorithms use the freedom to exchange rows and columns to minimize fill-in (entries which change from an initial zero to a non-zero value during the execution of an algorithm).

General treatment of orderings that minimize fill-in can be addressed using graph theory.

Applications

Solving linear equations

Given a matrix equation

A x = L U x = b \,

we want to solve the equation for x given A and b. In this case the solution is done in two logical steps:

  1. First, we solve the equation Ly = b for y
  2. Second, we solve the equation Ux = y for x.

Note that in both cases we have triangular matrices (lower and upper) which can be solved directly using forward and backward substitution without using the Gaussian elimination process (however we need this process or equivalent to compute the LU decomposition itself). Thus the LU decomposition is computationally efficient only when we have to solve a matrix equation multiple times for different b; it is faster in this case to do an LU decomposition of the matrix A once and then solve the triangular matrices for the different b, than to use Gaussian elimination each time.

Inverse matrix

When solving systems of equations, b is usually treated as a vector with a length equal to the height of matrix A. Instead of vector b, we have matrix B, where B is an n-by-p matrix, so that we are trying to find a matrix X (also a n-by-p matrix):

AX = LUX = B.

We can use the same algorithm presented earlier to solve for each column of matrix X. Now suppose that B is the identity matrix of size n. It would follow that the result X must be the inverse of A.[4]

Determinant

The matrices L and U can be used to compute the determinant of the matrix A very quickly, because det(A) = det(L) det(U) and the determinant of a triangular matrix is simply the product of its diagonal entries. In particular, if L is a unit triangular matrix, then

 \det(A) = \det(L) \det(U) = 1 \cdot \det(U) = \prod_{i=1}^n u_{ii}.

The same approach can be used for LUP decompositions. The determinant of the permutation matrix P is (−1)S, where S is the number of row exchanges in the decomposition.

See also

References

  1. ^ Poole, David (2006), Linear Algebra: A Modern Introduction (2nd ed.), Canada: Thomson Brooks/Cole, ISBN 0-534-99845-3 .
  2. ^ Golub, Gene H.; Van Loan, Charles F. (1996), Matrix Computations (3rd ed.), Baltimore: Johns Hopkins, ISBN 978-0-8018-5414-9 .
  3. ^ J.R. Bunch and J.E. Hopcroft, Triangular factorization and inversion by fast matrix multiplication, Mathematics of Computation, 28 (1974) 231–236.
  4. ^ Matrix Computations. 3rd Edition, 1996. p121.

External links

References

Computer code

Online resources



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